Задание 24 ЕГЭ по информатике · 3380E0

s = open('301_24.txt').read().strip()
left = 0
k = 0
right = 0
while k <= 100:
    if s[right:right+2] == 'AB':
        k += 1
    right += 1
mx = right - left - 1
while right < len(s):
    # сдвиг левого
    while s[left:left+2] != 'AB':
        left += 1
    left += 1
    # сдвиг правого
    while right < len(s) and s[right:right+2] != 'AB':
        right += 1
    right += 1
    mx = max(mx, right - left)
print(mx)
## 750
s = s.split('AB')
lens = [len(i) for i in s]
mx = 0
for i in range(len(lens) - 100):
    k = sum(lens[i:i + 101]) + 200 + 2
    mx = max(mx, k)
print(mx)